Does it pay to ask for a raise? A national survey of heads of households showed the percentage of those who asked for a raise and the percentage who got one. According to the survey, of the women interviewed, 25% had asked for a raise, and of those women who had asked for a raise, 46% received the raise. If a woman is selected at random from the survey population of women, find the following probabilities. (Enter your answers to three decimal places.)

Answer:Cross probabilityStep-by-step explanation:The type of probabilities remains to be determined. That is the question itself. The same problem is found in the book "Understanding basic statistics 7th edition of Brase".I will assume that the three probabilities to find are:a) p (woman asked for a raise)b) p (received raise | asked for one)c) p (received raise and asked for one)So,a) p(woman asked for a raise) It is given in the statement, so it is simple statistics:[tex]P_{WomA} =25%[/tex] b) p(received raise | asked for one) It is also found in the statement, however, now the formula would be given by:p(received raise | asked for one) = p(received raise and asked for one) / p(asked for one) [tex]P_{WomB}=46%[/tex]c) p(received raise and asked for one) For this case the formula is given differently and it is necessary to re-adjust formula B, as follows:p(received raise and asked for one) = p(received raise | asked for one) * p(asked for one)So,[tex]P_{WomC} = 0.46*0.25 = 11.5%[/tex]p(received raise and asked for one) = 11.5%